Latest activity

What's new New posts Latest activity
  • A
    Agent Smith replied to the thread 0.999....
    Si, in this case the dots have nothing to do with \infty and represent only missing information.
  • F
    fresh_42 replied to the thread 0.999....
    This is only valid if we speak of p-adic numbers. Those are a bit like Parias in mathematics...
  • A
    Agent Smith reacted to Steven G's post in the thread 0.999... with Like Like.
    Any positive number times infinity is infinity. \overline 9 is a positive number.
  • F
    fresh_42 replied to the thread 0.999....
    There is another possibility, points in between: 2013000\ldots 000:=20,130, \ldots,000, 000 =2.013\cdot 10^{16} but you have to write...
  • Steven G
    Steven G replied to the thread 0.999....
    Any positive number times infinity is infinity. \overline 9 is a positive number.
  • A
    Agent Smith replied to the thread 0.999....
    The dots represent nonzero digits and continue on forever in the direction the ellipsis appears. So 2013... is a number whose initial...
  • A
    Agent Smith reacted to fresh_42's post in the thread 0.999... with Like Like.
    Well, that is the problem! What are those dots? In 0.999\ldots they represent repeating nines, in 3.141592653589793238462 \ldots...
  • F
    fresh_42 replied to the thread 0.999....
    Well, that is the problem! What are those dots? In 0.999\ldots they represent repeating nines, in 3.141592653589793238462 \ldots...
  • A
    Agent Smith replied to the thread 0.999....
    I ask because for an irrational number like \pi = 3.14159..., I could say that if s = \text{the numerical string that is the decimal...
  • A
    Agent Smith replied to the thread 0.999....
    No, the dots are not 0's
  • A
    Agent Smith reacted to fresh_42's post in the thread 0.999... with Like Like.
    Not if the dots at the beginning represent zeros. Then it is simply 2013.
  • A
    Agent Smith replied to the thread 0.999....
    Thank you. So 3.14159... is ok but 2013... and ...2013 are not! For the reason that it implies I know something that I possibly can't...
  • F
    fresh_42 replied to the thread 0.999....
    Not if the dots at the beginning represent zeros. Then it is simply 2013.
  • A
    Agent Smith replied to the thread 0.999....
    Because ... that would mean I know the leading digits of \infty? 🤔
  • A
    Agent Smith reacted to blamocur's post in the thread 0.999... with Like Like.
    It's not.
Show older items
Top