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  • blamocur
    blamocur replied to the thread 0.999....
    It's not.
  • A
    Agent Smith replied to the thread 0.999....
    Haha. So 2013... = \infty? Gracias. Also is 2013... = \infty?
  • A
    Agent Smith reacted to fresh_42's post in the thread 0.999... with Like Like.
    Infinity cannot be treated like a number. If you want to have a calculus that deals with infinity as a separate admissible object, then...
  • A
    Agent Smith reacted to khansaheb's post in the thread 0.999... with Haha Haha.
    This must be that hallucination that some people are talking about.........
  • F
    fresh_42 replied to the thread 0.999....
    Infinity cannot be treated like a number. If you want to have a calculus that deals with infinity as a separate admissible object, then...
  • K
    khansaheb replied to the thread 0.999....
    This must be that hallucination that some people are talking about.........
  • A
    Agent Smith posted the thread 0.999... in Arithmetic.
    We know that 0.999... = 0.\overline 9 = 1 Does that mean ... 0.\overline 9 \times 10^\infty = 1 \times 10^\infty = 10... = \infty ...
  • K
    khansaheb replied to the thread Can it be natural?.
    I misunderstood the intended non-explicit requirement.
  • A
    Agent Smith reacted to Dr.Peterson's post in the thread Meaning and concept of space with Like Like.
    Does this help at all? https://en.wikipedia.org/wiki/Space_(mathematics) If not, what is lacking?
  • A
    Agent Smith reacted to BigBeachBanana's post in the thread Meaning and concept of space with Like Like.
    That depends on the context. Can you be more specific?
  • A
    Agent Smith reacted to Jignesh77's post in the thread Meaning and concept of space with Like Like.
    Good morning, I hope you're well and thank you in advance. I got Masters in Chemistry (1998) and studied maths till 12 grade(1994). I...
  • K
    khansaheb replied to the thread dividing a load of work correctly.
    Is this a problem that was assigned to you in an instructional class or a practical problem? The problem statement is vague - mainly...
  • Dr.Peterson
    Dr.Peterson replied to the thread Can it be natural?.
    But that has nothing to do with the question, which is to show either that there is some n for which the expression is a natural number...
  • K
    khansaheb replied to the thread Can it be natural?.
    Your OP did not explicitly say that. I was simply showing that the given expression need not produce natural number, for all 'n' (natural).
  • K
    khansaheb replied to the thread Can it be natural?.
    The above calculation is incorrect (due to temporary insanity)...... but the conclusion is correct. (5^2 - 1)/(4^2 - 1) = 24/15 =...
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