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    fresh_42 reacted to Agent Smith's post in the thread 0.999... with Like Like.
    Pythagoras, a charlatan?! 😄 Per the linked article on commensurability, incommensurability(a, b) = the nonexistence of a real c, and...
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    Agent Smith replied to the thread Terrence Howard Math?.
    Related is, cogito, my error, in thinking a number e.g. 9 is the 1 × 1 matrix [9]. 1 is a threshold for multiplication For a > 1, b >...
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    Agent Smith replied to the thread Terrence Howard Math?.
    Is 1^ \infty like \frac{0}{0}, indeterminate, instead of 1? We're not talking about any ol' number here, this is \infty. Perhaps 1 is...
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    Agent Smith reacted to blamocur's post in the thread Terrence Howard Math? with Like Like.
    The second equality.
  • blamocur
    blamocur replied to the thread Terrence Howard Math?.
    The second equality.
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    Agent Smith replied to the thread Can it be natural?.
    5^n = (4 + 1)^n = 4(k) + 1 Does that help?
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    Agent Smith replied to the thread Terrence Howard Math?.
    What's wrong with the following? \displaystyle \lim_{x \to \infty} \sqrt [x]2 = 1 2 = 1^\infty 1 \times 1 = 1^\infty Ergo, 2 = 1 \times 1
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    Agent Smith replied to the thread Could someone please help? best 6 papers turned in by 28 classes are re-read by organizers to ensure marking is correct..
    \frac{2}{28} \frac{2 \times 4}{28 \times 27} Right/wrong/both/neither?
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    Agent Smith reacted to blamocur's post in the thread Laplace Transforms with Like Like.
    Limits are in the formal definitions of both definite integrals and derivatives. But more to the point: \int_a^\infty f(x) dx =...
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    Agent Smith replied to the thread 0.999....
    Pythagoras, a charlatan?! 😄 Per the linked article on commensurability, incommensurability(a, b) = the nonexistence of a real c, and...
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    Agent Smith reacted to fresh_42's post in the thread 0.999... with Haha Haha.
    Yes, that's another issue. The digits depend on the number system that we use. Ok, \pi is unpredictable in every system, but...
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    fresh_42 replied to the thread 0.999....
    Yes, that's another issue. The digits depend on the number system that we use. Ok, \pi is unpredictable in every system, but...
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    Agent Smith replied to the thread 0.999....
    As you so correctly pointed to and I must admit, 0.14159... = \frac{14159...}{1000...} is not something I've seen in my mathematical...
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    fresh_42 replied to the thread 0.999....
    You really cannot deal with infinities as if they were numbers. And dots require a definition, or in many cases a convention we all...
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    Agent Smith replied to the thread 0.999....
    @fresh_42 , the above would be incorrect? 🤔 unless there's an infinity that begins 14159... and another infinity that begins 999.... 3...
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