Latest activity
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PCurious where he got the 0 from ? is e^infinity = 0 ?
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DDg1 replied to the thread Law of large numbers regression to mean.I got my terminology messed up sorry. Makes it hard to ask a question that doesn’t make sense when the terms don’t even make sense...
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Kkhansaheb replied to the thread Terrence Howard Math?.I agree totally it is a waste of time ............ 100%
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Ffresh_42 replied to the thread problem solving.The roots of p^2-p-1 are the golden ratio and its negative solution. This brings the Fibonacci numbers into the game. And...
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BigBeachBanana replied to the thread problem solving.My thought is to use proof by contradiction assuming \gcd(A, B ,C ,D) = k >1. -
Sstephanson12 replied to the thread problem solving.this means that n=p^3-p^2-p=p(p+1)(p-1)-p^2 = n but we need to prove this, but i don't knew how this looks a little bit like it; p|n...
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blamocur replied to the thread problem solving.This probably merits a separate thread in a different section, but: how much time does it make sense to spend helping with... -
The first 5 non-prime peculiars are 15, 95, 287, 1199, and 4607. As an interest in this problem, here's an Excel formula that checks if... -
This is what I get too. Also, it looks like all non-prime peculiars can be represented as n=p(p^2-p-1) where p is prime. At least all...
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The Highlander replied to the thread problem solving.As far as I can see, s/he's been given everything s/he needs to answer the question asked but appears to be reluctant to submit any...
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I'm often curious where an interesting problem comes from; the only other place I find this one (besides Math Forums) is here...
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Dr.Peterson replied to the thread problem solving.I'm often curious where an interesting problem comes from; the only other place I find this one (besides Math Forums) is here... -
The Highlander replied to the thread problem solving.The blue part (above) is just a direct copy of Massist's post in Math Forums! 🤷♂️ You appear to be just sitting back and waiting for...
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blamocur replied to the thread problem solving.This is what I get too. Also, it looks like all non-prime peculiars can be represented as n=p(p^2-p-1) where p is prime. At least all...
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Sstephanson12 replied to the thread problem solving.All primes are peculiar. If n=prime, d can be n or 1. -if d=1: d(d+1)=2 and this always is a divisor of n(n+1) -if d=n= d(d+1)=n(n+1)...
