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A
Agent Smith
replied to the thread
Terrence Howard Math?
.
Related is, cogito, my error, in thinking a number e.g. 9 is the 1 × 1 matrix [9]. 1 is a threshold for multiplication For a > 1, b >...
30 minutes ago
A
Agent Smith
replied to the thread
Terrence Howard Math?
.
Is 1^ \infty like \frac{0}{0}, indeterminate, instead of 1? We're not talking about any ol' number here, this is \infty. Perhaps 1 is...
Today at 6:04 AM
A
Agent Smith
reacted to
blamocur's post
in the thread
Terrence Howard Math?
with
Like
.
The second equality.
Today at 5:28 AM
blamocur
replied to the thread
Terrence Howard Math?
.
The second equality.
Today at 3:38 AM
A
Agent Smith
replied to the thread
Can it be natural?
.
5^n = (4 + 1)^n = 4(k) + 1 Does that help?
Today at 3:36 AM
A
Agent Smith
replied to the thread
Terrence Howard Math?
.
What's wrong with the following? \displaystyle \lim_{x \to \infty} \sqrt [x]2 = 1 2 = 1^\infty 1 \times 1 = 1^\infty Ergo, 2 = 1 \times 1
Today at 2:09 AM
A
Agent Smith
replied to the thread
Could someone please help? best 6 papers turned in by 28 classes are re-read by organizers to ensure marking is correct.
.
\frac{2}{28} \frac{2 \times 4}{28 \times 27} Right/wrong/both/neither?
Today at 2:04 AM
A
Agent Smith
reacted to
blamocur's post
in the thread
Laplace Transforms
with
Like
.
Limits are in the formal definitions of both definite integrals and derivatives. But more to the point: \int_a^\infty f(x) dx =...
Yesterday at 11:59 PM
A
Agent Smith
replied to the thread
0.999...
.
Pythagoras, a charlatan?! 😄 Per the linked article on commensurability, incommensurability(a, b) = the nonexistence of a real c, and...
Yesterday at 10:51 PM
A
Agent Smith
reacted to
fresh_42's post
in the thread
0.999...
with
Haha
.
Yes, that's another issue. The digits depend on the number system that we use. Ok, \pi is unpredictable in every system, but...
Yesterday at 10:16 PM
F
fresh_42
replied to the thread
0.999...
.
Yes, that's another issue. The digits depend on the number system that we use. Ok, \pi is unpredictable in every system, but...
Yesterday at 10:11 PM
A
Agent Smith
replied to the thread
0.999...
.
As you so correctly pointed to and I must admit, 0.14159... = \frac{14159...}{1000...} is not something I've seen in my mathematical...
Yesterday at 9:43 PM
F
fresh_42
replied to the thread
0.999...
.
You really cannot deal with infinities as if they were numbers. And dots require a definition, or in many cases a convention we all...
Yesterday at 9:11 PM
A
Agent Smith
replied to the thread
0.999...
.
@fresh_42 , the above would be incorrect? 🤔 unless there's an infinity that begins 14159... and another infinity that begins 999.... 3...
Yesterday at 8:42 PM
F
fresh_42
replied to the thread
0.999...
.
De nada.
Yesterday at 8:41 PM
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