# Activity Stream

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• Yesterday, 11:50 AM
I am having a bit of trouble with the following equation: (100p-4000/100p)=.3 Honestly, I don't know where to start with this one and would...
3 replies | 53 view(s)
• Yesterday, 11:09 AM
2+3=8, 3+7=27, 4+5=32, 5+8=60, 6+7=72, 7+8=?? Please Solve it?
2 replies | 62 view(s)
• Yesterday, 09:34 AM
What is the upper and lower bound of 44/3 sqaured
1 replies | 43 view(s)
• Yesterday, 03:50 PM
Let \nu\ge 1 be a parameter. For all t>0, we consider . . . . .\begin{align} A(t) & =\frac{1-\cos(t\sqrt{4\nu-1})}{4\nu-1}-(\cosh(t)-1) \\...
0 replies | 55 view(s)
• Yesterday, 09:42 AM
Aboard upriver tugboat, I leave with spinning head (7) 3 vowels inc'l 1 e
0 replies | 29 view(s)
• Yesterday, 11:05 PM
Hello, I have a question here which is giving me some problems. The question is in the picture below. I have already figured out number (i)...
0 replies | 19 view(s)
• Yesterday, 10:19 PM
Using those numbers, I was able to find the book online, and I see why you mentioned finding the solution without using Mathematica: that's how they...
12 replies | 176 view(s)
• Yesterday, 08:55 PM
What does "guest" mean?
7 replies | 145 view(s)
• Yesterday, 08:02 PM
w^2+2w-168=0 (x-12)(x+14)=0
5 replies | 145 view(s)
• Yesterday, 06:54 PM
Here is a discussion of this sort of problem, going into some depth for both a small problem like yours, and a large one (which would easily take the...
6 replies | 140 view(s)
• Yesterday, 06:17 PM
You are right man) I have searched for it in the internet, and I found couple algorithms that are based on trivial mutiplication. My teacher told me,...
6 replies | 140 view(s)
• Yesterday, 05:43 PM
I gave you what I had. Also, I am trying to find approximates. Sorry I didn't clarify that first. The answers they gave me were k1 is roughly...
12 replies | 176 view(s)
• Yesterday, 05:34 PM
Top one. Sorry, I don't know how to do equation formatting on the site yet.
3 replies | 53 view(s)
• Yesterday, 05:32 PM
Just for the sake of giving you some feedback you can't get when you teach yourself, we would say you "raised e to the 0 power", or something like...
12 replies | 176 view(s)
• Yesterday, 05:10 PM
Okay they are "Additive Inverses", but one normally would not drop the "Additive". I'm willing to submit to other opinions.
12 replies | 176 view(s)
• Yesterday, 03:55 PM
Does this mean that the "c" is multiplied on the k2, rather than being an exponent on k2? So the system is as follows? . . . . .0\, =\, k_1\,...
12 replies | 176 view(s)
• Yesterday, 03:43 PM
Are you studying something like what they discuss here? Also, are you working with "discrete" logs? Thank you! ;)
6 replies | 140 view(s)
• Yesterday, 03:42 PM
It is not a problem actually it's an equation that was given to me in this textbook I'm studying. The function is g(c) = k1ek2c + k3 The function...
12 replies | 176 view(s)
• Yesterday, 03:37 PM
The work I did showed that IF a given pair (S, U) is a solution of the system, THEN it must be (25, 65). If you don't see that, then you didn't...
7 replies | 150 view(s)
• Yesterday, 03:25 PM
As I read this, the original problem (which you really should have stated for us, to give us context) probably involved an equation something like A...
12 replies | 176 view(s)
• Yesterday, 03:20 PM
Oh and I have the answers by the way. This is actually not required by the book in using. I just would like to know so that I may be able to find 3...
12 replies | 176 view(s)
• Yesterday, 03:19 PM
Oh ok no probs was just looking for help. Like I like to help others with knowledge I have. But no worries I will look elsewhere. Delete my account...
7 replies | 145 view(s)
• Yesterday, 03:15 PM
I am teaching myself all this stuff so I'll preface with that. I took k1ek2(0) + k3 = 0 and multiplied 0 and k2 making it 0, then rose up e to 0...
12 replies | 176 view(s)
• Yesterday, 03:13 PM
What other solutions would be possible, aside of the one that makes both equations true at the same time? What other intersection point(s) do you...
7 replies | 150 view(s)
• Yesterday, 03:10 PM
This isn't one of those "cheetz" sites. Instead, the volunteers here give of their time, as they're able, to help students learn to do this stuff on...
2 replies | 62 view(s)
• Yesterday, 03:08 PM
Changing 2nd equation: S + U = 90 5S + 3U = 334 What do you get? Think about it...
7 replies | 150 view(s)
• Yesterday, 03:04 PM
This isn't one of those "cheetz" sites. Instead, the volunteers here give of their time, as they're able, to help students learn how to do things on...
7 replies | 145 view(s)
• Yesterday, 03:02 PM
Has your class not yet covered solving this sort of equation, so you haven't seen "multiplying both sides by the common denominator to clear the...
3 replies | 53 view(s)
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