# Activity Stream

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• Today, 12:02 PM
Romsek replied to a thread 3 rebuses in Math Odds & Ends
that was all Otis
12 replies | 396 view(s)
• Today, 10:42 AM
This is a very good question. Many decades ago, when logarithms were still heavily used for accurate computation, it was a very general convention...
3 replies | 46 view(s)
• Today, 10:39 AM
Denis replied to a thread 3 rebuses in Math Odds & Ends
https://www.youtube.com/watch?v=EDw4LdKFVxQ Very funny Romsek!! Thanks Otis.... late = 90% , never = 60% (4)
12 replies | 396 view(s)
• Today, 09:56 AM
You can choose what base to use; base 5 is convenient for some purposes, 10 or e for others.
3 replies | 46 view(s)
• Today, 09:55 AM
Your QM is clearly wrong, as it must depend on t. Try that again.
1 replies | 32 view(s)
• Today, 09:05 AM
I don't know how you got a "cosine" again in the integral. The integral \int cos(ax)dx is \frac{1}{a}sin(ax). However, the arclength of y= f(x)...
1 replies | 36 view(s)
• Today, 08:25 AM
The base can be any real number as long as you use same base on both sides. When the bases are not "explicitly" defined, the assumption is that...
3 replies | 46 view(s)
• Today, 07:13 AM
Points A and B have position vectors a and b. O is the origin and point P is such that OAPB is a parallelogram. a) Write down the position vector...
1 replies | 32 view(s)
• Today, 03:04 AM
say: x < 5y and I wanted to apply log to both sides: log x < log 5y What would the base be for each logarithm? Can we assume it is 10?...
3 replies | 46 view(s)
• Today, 12:33 AM
Hello, I am new to this forum and I apologise if I have placed this question in the wrong place and will move it if needed. I have a formula that...
1 replies | 36 view(s)
• Today, 12:20 AM
Otis replied to a thread 3 rebuses in Math Odds & Ends
You might try this. Not sure if Romsek tried without the hint, but my view differs. I think it's a dandy. :cool:
12 replies | 396 view(s)
• Yesterday, 10:45 PM
I don't claim to know anything about this, but it seems to me that the air is at sea level and is staying at sea level, so z=0. At least nothing...
1 replies | 127 view(s)
• Yesterday, 09:13 PM
Denis replied to a thread 3 rebuses in Math Odds & Ends
Yep...same as Otis' answer... meh = ?
12 replies | 396 view(s)
• Yesterday, 06:39 PM
Romsek replied to a thread 3 rebuses in Math Odds & Ends
**before and after** meh
12 replies | 396 view(s)
• Yesterday, 05:59 PM
How to do it depends on what identities you know (and are allowed to use). If you happen to have these available, it will take very little work: ...
2 replies | 126 view(s)
• Yesterday, 04:40 PM
Hi! So I am working through a problem for my meteorology class titled as "dynamic meteorology". I am asked to solve the total mechanical energy of...
1 replies | 127 view(s)
• Yesterday, 04:09 PM
tkhunny replied to a thread Prove in Calculus
In today's age, one could simply add them all up. 0.307... < 0.375 Perhaps regroup? 1/2 - 1/12 - 1/30 - 1/56 - ... etc. Will those terms be...
1 replies | 121 view(s)
• Yesterday, 03:58 PM
...but there is :) 1st step, divide by 2: x^2 - x + 2y = 6 2nd step, isolate y: y = (6 + x - x^2) / 2 Substitute in (Eq 1) You'll find...
2 replies | 144 view(s)
• Yesterday, 03:52 PM
What have you tried? First thing that came to my mind: 3 = 1+2 and 5 = 1+4
2 replies | 126 view(s)
• Yesterday, 03:03 PM
Since they said to eliminate y^2, I would do that, which is just what you did. (Or you could subtract the equations to eliminate x^2.) Now what? ...
2 replies | 144 view(s)
• Yesterday, 02:44 PM
Many thanks to those who helped me solve my last problem, I would appreciate any suggestions on this last question. I have listed the steps below...
2 replies | 144 view(s)
• Yesterday, 02:05 PM
redunken started a thread Prove in Calculus
Prove that...(pic)
1 replies | 121 view(s)
• Yesterday, 01:58 PM
prove the identity cosx-2cos3x+cos5x=2sinx(sin2x-sin4x)
2 replies | 126 view(s)
• Yesterday, 01:49 PM
Thanks both, thats clear!
3 replies | 139 view(s)
• Yesterday, 01:40 PM
You can see the graphs; GRAPH I GRAPH II Do they match?
3 replies | 139 view(s)
• Yesterday, 01:20 PM
At least you could be honest: you came here for the answer and not really help. \dbinom{11}{6}=462 ways to pick six from eleven. SEE HERE.
8 replies | 364 view(s)
• Yesterday, 12:56 PM