Am stuck showing: P(AUBUC)=P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)

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Kitimbo

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Given A,B and C are events in the same experiment.
Show that P(AUBUC)=P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)


Forgive me for not showing any working but I don't uderstand this probability no
 
Kitimbo said:
Given A,B and C are events in the same experiment.
Show that P(AUBUC)=P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)

Forgive me for not showing any working but I don't uderstand this probability no
Click to expand...
Has your class covered set-notation statements of probability at all? Have you studied how to throw out double-counted events?

Thank you! ;)
 
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