Hi all
I just joined this forum as I was looking for help with a probability question that I can't figure out the answer to:
If you have 64 players in an open tennis draw, and 16 of those players are seeded (i.e. Cannot be drawn against each other in round 1) then what is the probability that a random unseeded player is drawn against a seed in the first round?
My theory is that it is 1/3. This is because the 16 seeded players enter the draw, leaving 48 unseeded players to be drawn. Therefore the chances are 16/48 that the remaining unseeded players are drawn against a seed.
However, my friend says that that is conplicating it. He says that since 16 of the 32 round 1 matches have a seed in it, the chances are simply 1/2 of meeting a seed.
I disagree but wondered if anyone would be able to explain if either of the above two options is correct, or if we are both wrong.
Any help appreciated!
eeay17
I just joined this forum as I was looking for help with a probability question that I can't figure out the answer to:
If you have 64 players in an open tennis draw, and 16 of those players are seeded (i.e. Cannot be drawn against each other in round 1) then what is the probability that a random unseeded player is drawn against a seed in the first round?
My theory is that it is 1/3. This is because the 16 seeded players enter the draw, leaving 48 unseeded players to be drawn. Therefore the chances are 16/48 that the remaining unseeded players are drawn against a seed.
However, my friend says that that is conplicating it. He says that since 16 of the 32 round 1 matches have a seed in it, the chances are simply 1/2 of meeting a seed.
I disagree but wondered if anyone would be able to explain if either of the above two options is correct, or if we are both wrong.
Any help appreciated!
eeay17