Desert Fox
New member
- Joined
- Jul 19, 2017
- Messages
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We have 5 types of ice-cream: vanilla, banana, coconut, chocolate, forest fruits. And we have 4 types of syrup: strawberry, raspberry, blueberry, caramel. A person buys a portion of ice-cream (we are considering random choice here!) . The portion contains three different types of ice-cream and two different types of syrup.
What is the probability (expressed in percents) of a portion containing banana ice-cream and caramel syrup?
I am in big struggle to find the solution. I need a clear, stand-by-step solution.... and a remark of the required formulas for the solution.
Here it is my attempt, please, correct me if i am wrong:
For ice-cream: he can choose 3 different types out of 5. So, there is 3/5 probability of containing banana ice-cream.
For syrup: he can choose 2 different types out of 4. So, there is 2/4 probability of containing caramel syrup.
Hence, the probability of a portion containing banana ice-cream and caramel syrup is: 3/5 multiplied by 2/4 = 6/20, which is exactly 30%.
So, my answer is: 30%
But in my textbook (where I have the answer, but I don't have the solution) the given answer is: 15%
Where I am wrong??? Please, help....
[/FONT]What is the probability (expressed in percents) of a portion containing banana ice-cream and caramel syrup?
I am in big struggle to find the solution. I need a clear, stand-by-step solution.... and a remark of the required formulas for the solution.
Here it is my attempt, please, correct me if i am wrong:
For ice-cream: he can choose 3 different types out of 5. So, there is 3/5 probability of containing banana ice-cream.
For syrup: he can choose 2 different types out of 4. So, there is 2/4 probability of containing caramel syrup.
Hence, the probability of a portion containing banana ice-cream and caramel syrup is: 3/5 multiplied by 2/4 = 6/20, which is exactly 30%.
So, my answer is: 30%
But in my textbook (where I have the answer, but I don't have the solution) the given answer is: 15%
Where I am wrong??? Please, help....
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