Random Number Generator Problem, All Help Appreciated :)

skypilot

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Joined
Sep 11, 2017
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Hello forum please help me with this problem,

I'm trying to catch a pokemon (yes please bear with me) whose has 6 attributes, each attribute is given a random number value ranging from 0 to 31 (32 possible results). An example would be 0/ 31/ 28/ 12/ 3/ 20. Each ot the attribute value is randomly generated and independent of each other.

However I'm able to manipulate any 3 of the 6 attributes to be garuanteed 31. Any meaning in no particular where they are garuanteed to be 31. An example of this would be: 31/ 31/ 31/ 0/ 20/ 7 or 31/ 11/ 8/ 31/ 31/ 2. Again the 3 remaining random numbers are independently generated & no effect on each other.

So my questions are:

1) What is the probability that out of the three remaining attributes I will get 2 more 31? An example would be 31/31/31/31/7/31? I've seen discusstion where people put the odds to be 1/200, now I understand that even if I catch 200 pokemons I might not get one with 5 perfect 31, so would catching 400 increase the probability of catching one with 5 attribute of 31?

2) What is the probability of catching a pokemon with a random generated attributes of all 31? Meaning all 6 attributes? i.e 31/31/31/31/31/31?

Thank you very much for your time and please help me out!
 
Hello forum please help me with this problem,

I'm trying to catch a pokemon (yes please bear with me) whose has 6 attributes, each attribute is given a random number value ranging from 0 to 31 (32 possible results). An example would be 0/ 31/ 28/ 12/ 3/ 20. Each ot the attribute value is randomly generated and independent of each other.

However I'm able to manipulate any 3 of the 6 attributes to be garuanteed 31. Any meaning in no particular where they are garuanteed to be 31. An example of this would be: 31/ 31/ 31/ 0/ 20/ 7 or 31/ 11/ 8/ 31/ 31/ 2. Again the 3 remaining random numbers are independently generated & no effect on each other.

So my questions are:

1) What is the probability that out of the three remaining attributes I will get 2 more 31? An example would be 31/31/31/31/7/31? I've seen discusstion where people put the odds to be 1/200, now I understand that even if I catch 200 pokemons I might not get one with 5 perfect 31, so would catching 400 increase the probability of catching one with 5 attribute of 31?

2) What is the probability of catching a pokemon with a random generated attributes of all 31? Meaning all 6 attributes? i.e 31/31/31/31/31/31?

Thank you very much for your time and please help me out!
Is 1/ 31/ 31/ 0/ 20/ 7 different from Is 31/ 1/ 31/ 0/ 20/ 7?
 
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