Let A be the width of a 95% Confidence interval for population mean based on a sample of size n=20 taken from a normal population with sigma=0.5
Let B b the width of a 95 confidence interval for population mean based on a sample size 3 times n taken from the same normal population with sigma=0.5
Calculate how much bigger A is then B, that is calculate the ratio A/B.
What I have done:
Width=Z(sima/SQRT(n))
For A- n is <30 soused Z=1.645 in the equation and subbed A for the width solve for A
For B- n=(3)(20)=60 which is>30 so used t=2.093 and got the equation B= 2.093*(.5/SQRT(60)) the soled for B
Using my values I found A/B but that wasn't right.
Thought
I think may have gone wrong in the equation because I am thinking that the equation is only for half the Confidence interval s wen set up he equation I should b using A/2=equation ad/2= equation
OR I am messing up the Z an t usage
OR both ha
Let B b the width of a 95 confidence interval for population mean based on a sample size 3 times n taken from the same normal population with sigma=0.5
Calculate how much bigger A is then B, that is calculate the ratio A/B.
What I have done:
Width=Z(sima/SQRT(n))
For A- n is <30 soused Z=1.645 in the equation and subbed A for the width solve for A
For B- n=(3)(20)=60 which is>30 so used t=2.093 and got the equation B= 2.093*(.5/SQRT(60)) the soled for B
Using my values I found A/B but that wasn't right.
Thought
I think may have gone wrong in the equation because I am thinking that the equation is only for half the Confidence interval s wen set up he equation I should b using A/2=equation ad/2= equation
OR I am messing up the Z an t usage
OR both ha