Assume I have a method of playing Blackjack where during 2/3 of all Blackjack hands I am at a
1/2% Negative edge and for the remaining 1/3 of hands I have a
Positive edge of 1/2%, and I know in advance whether the next hand will be a positive or negative edge type hand, if I bet $1.00 during the negative edge hands
and $10.00 during the positive edge hands what is my "Expectation"? Can it be expressed as a percentage also, such as "I have a Y % positive edge in this game"
I tried to solve it in the fashion show below:
66.7 hands X -.005 X $1.00 = minus 33 cents AND then 33.3
hands X .005 X $10.00 = + $ 1.66 . So, Over 100 hands I should
be ahead on average, over many 100 hand trials, $1.66 - .33 which =
$1.33. Then to find my overall % edge I took the $ 1.33 and
divided it by the total amount of dollars player in the 100 hands,
which gives : $1.33 / $399.70 = +.003 or what I interpret to
be 3/10 ths of 1%. Do you think my math is correct here ??? Thanks,
1/2% Negative edge and for the remaining 1/3 of hands I have a
Positive edge of 1/2%, and I know in advance whether the next hand will be a positive or negative edge type hand, if I bet $1.00 during the negative edge hands
and $10.00 during the positive edge hands what is my "Expectation"? Can it be expressed as a percentage also, such as "I have a Y % positive edge in this game"
I tried to solve it in the fashion show below:
66.7 hands X -.005 X $1.00 = minus 33 cents AND then 33.3
hands X .005 X $10.00 = + $ 1.66 . So, Over 100 hands I should
be ahead on average, over many 100 hand trials, $1.66 - .33 which =
$1.33. Then to find my overall % edge I took the $ 1.33 and
divided it by the total amount of dollars player in the 100 hands,
which gives : $1.33 / $399.70 = +.003 or what I interpret to
be 3/10 ths of 1%. Do you think my math is correct here ??? Thanks,