You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an alternative browser.
You should upgrade or use an alternative browser.
Answers without negative exponents!
- Thread starter sana125
- Start date
Hello, sana125!
Are you in self-study?
It's hard to believe that this wasn't covered in class.
. . . Definitely NOT what I'd call "Intermediate/Advanced Algegra".
Are you in self-study?
It's hard to believe that this wasn't covered in class.
Adding two polynomials was covered in the first week of Algebra I.Perform the indicated operations. Give the answers without negative exponents!
(5x<sup>2</sup> - x + 2) + (x<sup>3</sup> + 2x - 3)
.
. . . Definitely NOT what I'd call "Intermediate/Advanced Algegra".
I don't see any negative exponents . . . do you?(a<sup>2</sup>b<sup>3</sup>c<sup>4</sup>/3a<sup>3</sup>b<sup>5</sup>c)<sup>3</sup>
.
(a^2b^3c^4/3a^3b^5c)^3
Work inside the parentheses first. (Note the negative exponents that appear – and then disappear.)
(a^2)/(a^3) = a^(2-3) = a^(-1) = 1/a
(b^3)/(b^5) = b^(3-5) = b^(-2) = 1/(b^2)
(c^4)/(c) = c^(4-1) = c^3
Therefore,
(a^2b^3c^4/3a^3b^5c)^3 = ((c^3)/(a(b^2))^3
= ((c^9)/((a^3)(b^6))