Dimensions of a Window

The area of the opening of a rectangular window is to be 143 square feet. If the length is to be 2 feet more than the width, what are the dimensions?

I once had a student who used this solution algorithm.
(Note: This is NOT to be construed as a description of you. It's just an example of a solution algorithm that I actually have encountered. Sadly, it isn't that uncommon.)

1) I know I can't do it, so why try?!
2) I don't understand what I'm supposed to do, so I'll just give up.
3) When will I EVER use this garbage in REAL life?
4) I'll never be any good at math.
5) I hate this trash. Why do I have to take it? :x
6) I'll never be able to graduate.
7) I just don't get it! :?
8) I'll call {fill in a friend's name} and go hang out at the mall.
9) My stupid Mom won't let me go to the mall until I finish my homework. :roll:
10) I wonder how many holes there are in the ceiling?

Guess how many problems this student solved?

Show us your substantially more serviceable algorithm.
Give us a flavor of how you might approach such a problem statement.

My Reply...

First of all, I did not like what you so intelligently implied.
Secondly, here is my TRY as you said:

The area of the opening of a rectangular window is to be 143 square feet. If the length is to be 2 feet more than the width, what are the dimensions?

W = x

L = x + 2

Area = 143 sq. ft.

Area of rectangle formula: A = LW

143 = (x+2)(x)

143 = x^2 + 2x

x^2 + 2x - 143 = 0

Do I need to use the quadratic formula here?

Well, maybe you did need the push. You done perfect :!:
You can use the formula or you can notice the factors of 143 are 11 and 13
the +2x term says it factors into
(x+13)(x-11)
x=-13 dosent sound too good so x=11 is a good answer.

Gene

Gene,

Like always, thank you for your patience and helpful math notes.

You seem to have missed my "Note". I implied nothing. Please don't remove deliberate context just so you can feel bad.

Your algebra was delightful. EXCELLENT work!!!!