probability problem

G

Guest

Guest
In a group of 10 people, 60 percent have brown eyes, two people are to be selected at random from the group.
What is the probability that neither person selected will have brown eye?
 
10 people; 6 have brown eyes, 4 don't.

1st pick does not have brown: 4 out of 10 = 4/10

Now, one non-brown is out; 9 people left, 3 with non-brown; so:
2nd pick does not have brown: 3 out of 9 = 3/9

So probability = 4/10 * (3/9) ; OK?
 
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