kris10 said:Joe has $3.75 in quarters,dimes and nickels. He has twice as many quarters as dimes and three more dimes than nickels. Find how much of each coin Joe has.
Denis said:10d + 25(2d) + 5(d - 3) = 375
Denis said:kris10 said:Joe has $3.75 in quarters,dimes and nickels. He has twice as many quarters as dimes and three more dimes than nickels. Find how much of each coin Joe has.
d = dimes
2d = quarters : twice as many quarters as dimes
d-3 = nickels : three more dimes than nickels
.10d + .25(2d) + .05(d - 3) = 3.75
you can multiply that by 100 to make it easier to solve:
10d + 25(2d) + 5(d - 3) = 375
Can you finish it?