can somebody please help me

Work from the inside out. First, take the "-3" through the parentheses. Then combine the "1" with the "-6" inside the brackets. Then take the "-2" through the brackets. Combine the "3x" with the "6x". This should give you:

. . . . .9x + 10 = 2x

Subtract "9x" from both sides, and then divide through by "-7" to get your final answer.

Eliz.

Edit: Dropped a "minus" sign. Ugh!
 
Math Idiot said:
this is due tomorrow 3x-2[1-3(x+2)]=2x
Well, if you're a "math idiot", what's the use? Please go buy a better attitude.

Learn the "Order of Operations".

3x-2[1-3(x+2)]=2x

Apply the Distributive Property of Multiplication over Addition to the inner-most parentheses.

3x-2[1-3x-6]=2x

Simplify inside the brackets

3x-2[-3x-5]=2x

Apply the Distributive Property of Multiplication over Addition to the parentheses.

3x+6x+10=2x

Simplify the left-hand side

9x+10=2x

I'm tired. You do the rest.
 
3x-2[1-3(x+2)]=2x

3x -2(1-3x-6) =2x

3x-2+6x+12 =2x

ok your turn................
 
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