(5a^3 – 4a – 5) + (2a^3 – 2a + 3) =(5a^3 +2a^3)+(-4a-2a)+(-5+3)
L latresa31s Junior Member Joined Sep 4, 2005 Messages 135 Sep 15, 2005 #1 (5a^3 – 4a – 5) + (2a^3 – 2a + 3) =(5a^3 +2a^3)+(-4a-2a)+(-5+3)
L latresa31s Junior Member Joined Sep 4, 2005 Messages 135 Sep 15, 2005 #3 (5a^3 – 4a – 5) + (2a^3 – 2a + 3) =(5a^3 +2a^3)+(-4a-2a)+(-5+3) =(5a^3 + 2a^3) + [-4a(-2a)] + [-5+3] =[(5-2)a^3] + [(-4-2)a] +[-5+3] =3a^3 + (-6a) +(-2) =3a^3-6a-2
(5a^3 – 4a – 5) + (2a^3 – 2a + 3) =(5a^3 +2a^3)+(-4a-2a)+(-5+3) =(5a^3 + 2a^3) + [-4a(-2a)] + [-5+3] =[(5-2)a^3] + [(-4-2)a] +[-5+3] =3a^3 + (-6a) +(-2) =3a^3-6a-2
G Guest Guest Sep 15, 2005 #4 =(5a^3 + 2a^3) + [-4a(-2a)] + [-5+3] = ( (5+2) a^3) ........rest is correct