(4x^5y^0/z^3)^-2 =(4*x^5*y^0)^-2 =(4*x^5*z^3)^-2 =(z^6)x/[(16)(x^10)] is this problem correct?
L latresa31s Junior Member Joined Sep 4, 2005 Messages 135 Sep 18, 2005 #1 (4x^5y^0/z^3)^-2 =(4*x^5*y^0)^-2 =(4*x^5*z^3)^-2 =(z^6)x/[(16)(x^10)] is this problem correct?
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Sep 18, 2005 #2 Hello, latresa31s! (4x<sup>5</sup>y<sup>0</sup>/z<sup>3</sup>)<sup>-2</sup> = (4x<sup>5</sup>y<sup>0</sup>)<sup>-2</sup> . . . . don't what you did here; what happened to the z ? = (4x<sup>5</sup>z<sup>3</sup>)<sup>-2</sup> . . . . oh, there it is! = (z<sup>6</sup>)x/(16x<sup>10</sup>) . . . . but this is very close is this problem correct? Click to expand... Since y<sup>0</sup> = 1, we have: . (4x<sup>5</sup>/z<sup>3</sup>)<sup>-2</sup> .= .(4<sup>-2</sup>)(x<sup>5</sup>)<sup>-2</sup> / (z<sup>3</sup>)<sup>-2</sup> . . . . = .(4<sup>-2</sup>)x<sup>-10</sup> / z<sup>-6</sup> .= .(z<sup>6</sup>) / (16x<sup>10</sup>)
Hello, latresa31s! (4x<sup>5</sup>y<sup>0</sup>/z<sup>3</sup>)<sup>-2</sup> = (4x<sup>5</sup>y<sup>0</sup>)<sup>-2</sup> . . . . don't what you did here; what happened to the z ? = (4x<sup>5</sup>z<sup>3</sup>)<sup>-2</sup> . . . . oh, there it is! = (z<sup>6</sup>)x/(16x<sup>10</sup>) . . . . but this is very close is this problem correct? Click to expand... Since y<sup>0</sup> = 1, we have: . (4x<sup>5</sup>/z<sup>3</sup>)<sup>-2</sup> .= .(4<sup>-2</sup>)(x<sup>5</sup>)<sup>-2</sup> / (z<sup>3</sup>)<sup>-2</sup> . . . . = .(4<sup>-2</sup>)x<sup>-10</sup> / z<sup>-6</sup> .= .(z<sup>6</sup>) / (16x<sup>10</sup>)