PLEASE help ASAP

nina

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Dec 7, 2005
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A and B working together can do a job in 24 hours. If A works alone for 6 hours and B finishes the job in 36 hours, how many hours would it take each working alone to do the job? Answer is (60 hours, 40 hours)

Please help me try and figure out how to get this answer all I've come up with is: 1/x+6 *24 + 1/y+36*24=1
24/x+6 + 24/y+36=1
 
nina said:
A and B working together can do a job in 24 hours. If A works alone for 6 hours and B finishes the job in 36 hours, how many hours would it take each working alone to do the job? Answer is (60 hours, 40 hours)

Please help me try and figure out how to get this answer all I've come up with is: 1/x+6 *24 + 1/y+36*24=1
24/x+6 + 24/y+36=1
First, you need a CLEAR definition. What are 'x' and 'y'?

Name stuff.

x = hours required for A to finish the job alone
y = hours required for B to finish the job alone

"A and B working together can do a job in 24 hours."

1/x + 1/y = 1/24 -- Right?

1/x = jobs A can finish in one hour
1/y = jobs B can finish in one hour

"If A works alone for 6 hours and B finishes the job in 36 hours"

6*(1/x) + 36*(1/y) = 1 job

I get x = 60 and y = 40. Can you get those from the equations?
 
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