three cousins

jamesp22

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Joined
Dec 8, 2005
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Three cousins, product of their ages is 84. Next year the youngest will be 1/4 the age of the middle cousin. In 2 years the oldest will be twice the current age of the middle cousin. What is the age of the oldest cousin?
 
A < B < C
A+1= 1/4(B+1) so B=4(A+1)-1
C+2=2B so C = 2B-2 = 2(4(A+1)-1)-2
ABC=84
A*(4A+3)*(2(4(A+1)-1)-2) = 84
Solve for A
Hint: A is a positive integer smaller than 84^(1/3) so trial and error is easiest.
 
Re: Yes!

Makayla52 said:
I could not agree with you more.
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Eliz.
 
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