new type to simplifie and not sure where to start???

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#1 mn^-9m^30/m^0m^23


and #2y(x^-3/y^-5)^-1 times x(y^3/x^-3)^-3


I'm lost at where to strt but he has for #1 x^3y^9 and #2 m^53/n^9 is he close?? if I can get them figured out we will work them together in the morning before school I don't just give him the answers but I'm not sure where to start on these??? :(
 
4 little piggies mom said:
#1 mn^-9m^30/m^0m^23


and #2y(x^-3/y^-5)^-1 times x(y^3/x^-3)^-3


I'm lost at where to strt but he has for #1 x^3y^9 and #2 m^53/n^9 is he close?? if I can get them figured out we will work them together in the morning before school I don't just give him the answers but I'm not sure where to start on these??? :(
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Start in the same place EVERY time. Simplify if Possible, then Gather!

mn^-9m^30/m^0m^23 = m^(1+30-0-23) * n^(-9) -- Now what?

[y(x^-3/y^-5)^-1]*[x(y^3/x^-3)^-3] = [y/(x^-3/y^-5)]*[x/(y^3/x^-3)^3] =
[y*y^(-5)*x^3]*[x/(y^9/x^-9)] = ?? You do the rest.

Just go through slowly and deliberately, ONE step at a time.
 
am I right or at least close???

1. m^7/n^9

2. I get x^6 but I don't think I'm using the first y or x in the problem??? because I get that or x^12/y^12

do you have y/x^4/y^6 how I din't know you couls have a/a/b for example??? :oops:
 
I think I finally got the answer will some one please check

#1 I came up with m^54/n^9

#2 I finlly got 1/x^5y^13 :)
 
finally I think i got it....

so after all your help and lots of work I cme up with m^8/n^9 for #1 is that the finally answer?
:?
 
YES!! Attaboy, mom :wink:

mn^-9m^30/m^0m^23

Take your time with these;
left side: m * m^30 = m^31 ; so we now have m^31 n^(-9)
right side: since m^0 = 1, then we have simply m^23

So equation is now: m^31 n^(-9) / m^23

Perform up and down move:
m^31 m^(-23) / n^9

Complete:
m^8 / n^9
 
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