quadratic polynomial

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moronatmath

Junior Member
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Feb 14, 2006
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Could someone help me with this?

give a quadratic polynomial which has zeros at 10 and 7.


give a quadratic polynomial which has zeros at -3 and 10.

give a quadratic polynomial which has a double root at 9.
 
Just work backwards.

If (x - a)(x - b) = 0, then the quadratic has zeroes at x = a and x = b.

Working backwards, if the quadratic has zeroes at x = a and x = b, then x - a = 0 and x - b = 0, so x - a and x - b were factors, so the quadratic is (x - a)(x - b), which you would then multiply out and simplify.

Eliz.
 
Thank you for that tkhunny
Enter a quadratic polynomial which has zeros at -3 and 10
(x+3)(x-10)

Simple enough!

Could someone fill me in what double root is?
Enter a quadratic polynomial which has a double root at 9?
 
Same as the others.
(x-a)(x-a) has a double root at a.
 
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