square root problem

sross002

New member
Joined
Jan 19, 2006
Messages
6
Please excuse the absence of the square root symbols...

I know the answer is x = sqrt(3) but i can't figure out how to get it, please help...

question:
3x+x sqrt(3) = 3 + 3 sqrt(3)
 
Factor out the x.

Divide off what you just factored the x out of.

Rationalize the denominator of the right-hand side.

Eliz.
 
3x+x sqrt(3) = 3 + 3 sqrt(3)

i'll just show you the equation

3x + x√3 = 3 + 3√3
Is this the equation? if it is i'll go on and if it's not, do the samething with your equation

(3x + x√3)^2 = (3 + 3√3)^2

9x^2 + 3x^2 = 9 + 27

12x^2 = 36

x^2 = 3

x = √3


this is only 1 way of doing it, and i bet there's few more but this is just the way i did it, hope this helps[/img]
 
aznfury363 said:
3x+x sqrt(3) = 3 + 3 sqrt(3)

i'll just show you the equation

3x + x?3 = 3 + 3?3
Is this the equation? if it is i'll go on and if it's not, do the samething with your equation

(3x + x?3)^2 = (3 + 3?3)^2

9x^2 + 3x^2 = 9 + 27

12x^2 = 36

x^2 = 3

x = ?3


this is only 1 way of doing it, and i bet there's few more but this is just the way i did it, hope this helps[/img]

Whoa!! You are squaring binomials here.

(3x + x √3)<SUP>2</SUP> = (3 + 3 √ 3)<SUP>2</SUP>

9x<SUP>2</SUP> + 6x<SUP>2</SUP>√3 + 3x<SUP>2</SUP> = 9 + 18 √3 + 27

12x<SUP>2</SUP> + 6x<SUP>2</SUP> √3 = 36 + 18 √3

Now, I don't see that this is a big improvement over what you started with.

Go with Eliz.'s approach. Factor the left side:

x(3 + √3) = 3 + 3 √3
Divide both sides by (3 + √3):

x = (3 + 3 √3)/(3 + √3)

Rationalize the denominator of the right side. Multiply numerator and denominator by (3 - √3)....I'll let you finish it.
 
(3x + x √3)2


doesn't the ^2 apply to every number in the equation?
 
You better get back to basics, fury.

(x + y)^2 = x^2 + 2xy + y^2

x + y
x + y : now multiply them
 
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