this problem is probably super easy but im so lost

Eva Barragan

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Feb 8, 2006
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anytime i see problems like this one i get so confused i dont know why i just do
anyone who can explain this problem to me your help is much appreciated
derrictions are: Simplify. Assume varriables are nonnegative.
the problem is
sqrt[64/x^4]
im so confused im thinking the awnser might be 4/x^2 how i got that im not sure?
:cry:
thank you
im so lost
 
you seem to have the right idea, but what is the square root of 64?
 
sqrt[64/x^4]

that's same as sqrt(64) / sqrt(x^4) : less confusing ?
 
thanx for replying
it knida helps i mean the sqrt of 64 is sqrt of [8]

so thats how i got the awnser of 4/x^2
can u show me what i did wrong
thanx
 
8*8=64 so sqrt(64) = 8, not 4.
Think about that and look at Denis' hint.
--------------
Gene
 
kay sorry its just that i thought uleft the sqrt sighn stayed wich is y i put 4/x^2
so then is the awnser 8/x^2
or 8x^2
now im confused
 
I'm sorry too. I don't understand what you are saying.
i thought uleft the sqrt sighn stayed wich is y i put 4/x^2
\(\displaystyle sqrt(64) = 8\)
When you have taken the root, you are done with the sign. It is gone. You did it with \(\displaystyle sqrt(x^4) = x^2\)
As Denis said, you can "split up" the \(\displaystyle sqrt(64/x^2)\) into \(\displaystyle sqrt(64)\) and \(\displaystyle sqrt(x^4)\) then put them back together as 8/x^2.

PS. Please don't abandon writing in English. Chatspeak really grates on our nerves.
 
o sorry about the way i wrote didnt relise i did it
sorry
well anyways thankyou so much for you help i realy do appreciate it
thanks :D
 
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