functions of a domain

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How would I figure this one out?

What is the domain of the function y= sqrt 3x?

I think its the set of all real numbers except 0?
 
Zero is an acceptable value. \(\displaystyle \L\\ \sqrt{0}=0\)
 
so if x were negative it would make all real numbers except -3 possibly?
 
What? Think that out a little better.

-1*3 = -3 sqrt(-3) = ???
-2*3 = -6 sqrt(-6) = ??
-9*3 = -27 sqrt(-27) = ??
 
boscothepug1 said:
How would I figure this one out?

What is the domain of the function y= sqrt 3x?

I think its the set of all real numbers except 0?

In the set of real numbers, you can only take the square root of something which is greater than or equal to 0.

Since y = √(3x)
we know that 3x >= 0

Now, solve that for x, and you'll have the domain.
 
Throwing darts is not a good plan. You must KNOW the answer.

Think really hard on what you have been told.

3x >= 0 ==> x >= 0

Does that describe ALL Real Numbers?
 
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