Two-Digit word problems...oh boy

streetglow50

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Feb 27, 2006
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srry, i can't show any work becuase i have no idea how to solve this problem on my homework:

A certain two-digit number has a value that is 3 more than 4 times the sum of its digits. The units digit is two more than the tens digit. Find the number.

Help would be appreciated. :)
 
A certain two-digit number has a value that is 3 more than 4 times the sum of its digits. The units digit is two more than the tens digit. Find the number.

1--Let the 2 digit number be 10A + B.
2--Then, 10A + B = 4(A + B) + 43
3--Also, B = A + 2

I'm confident you can take it from here.
 
ah. thank you. i mostly just have problem with writing the equation.

once i get the equation written, the rest is easy for me.
 
My apologies. The 4 does not belong there.

A certain two-digit number has a value that is 3 more than 4 times the sum of its digits. The units digit is two more than the tens digit. Find the number.

1--Let the 2 digit number be 10A + B.
2--Then, 10A + B = 4(A + B) + 3
3--Also, B = A + 2
 
streetglow50 said:
Based on what you told me, i got

A=17

TchrWill gave you the two equations:
A = ten's digit
B = units digit

10A + B = 4(A + B) + 3
B = A + 2

Show us HOW you got A = 17. Could the ten's digit of a two-digit number be 17? I don't think so.

If we can see your work, we can help you find your mistake.
 
i got A=3.67.

Tchr made a mistake, so my answer came out as 17. after he fixed his mistake, i got 3.67.

Ok, this homework has droven me mad... :evil: I'm just going to get help from my algebra teacher in the morning. :cry:
 
He told you
10A + B = 4(A + B) + 3
B = A + 2
Show us how you got
a=3.67
Hint: It should be between 1 and 9.
 
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