Have to do this in graph formation. This is what I came up with: Distance for both are 30. Rate for cyclist is 2x. Rate for the jogger is x. Don't know where time fits into equation though. The only formula I could come up with was 30/2x = 30/x but that doesn't work out.
thanks
Problem:
A cyclist and a jogger both leave san antonio at 6:00 pm heading to the supermarket, which is 30 miles away. The cyclist is traveling twice as fast as the jogger and arrives at the supermarket three hours before the jogger. Find the cyclist's speed.
thanks
Problem:
A cyclist and a jogger both leave san antonio at 6:00 pm heading to the supermarket, which is 30 miles away. The cyclist is traveling twice as fast as the jogger and arrives at the supermarket three hours before the jogger. Find the cyclist's speed.