Math help please

I cant get this one because its supposed to be odd and add to 70 but 70 is even heres the p[roblem if anyone can help i greatly appreciate it.

Find three consecutive odd integers such that the sum of the first, two times the second and three times the third is 70.


Does anyone know

But 2 times the second is even. Odd+evev+odd is even.
The numbers are 2x+1, 2x+3 and 2x+5
(2x+1)+2(2x+3)+3(2x+5) = 70.
Solve for x then reconstruct the three numbers.

Alternatively and nearly identical:

A + 2(A + 2) + 3(A + 4) = 70

6A = 54 making A = 9, B = 11 an C = 13.