need help with solve the slope intercept form

lost here

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Mar 2, 2006
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2x - y = -4
(slope-intercept form)
solve the equation with y

2x -y = - 4
-2x -2x

-y= -2x -4

y= - 2x - 4
1

Slope is - 2
1

y-intercept is (0,- 4)

I am not sure if I am doing this right someone told me I am doing it wrong?[/list][/u]
 
lost here said:
2x -y = - 4
-y= -2x -4
y= - 2x - 4
On what basis did you change the sign on the terms of one side of the equation (and not the other)?

Thank you.

Eliz.
 
I don't think it come out the way I wrote it

2x - y = -4
-2x -2x ( substract 2x from both side)

-y= -2x-4 (divide -y to both side)
-1 -1


y= -2/1x - 4

slope is -2/1
y intercept is (0.- 4)

not sure this is what the teacher told me to do. I am confuse
 
lost here said:
-y= -2x-4 (divide -y to both side)
-1 -1
Do you maybe mean "divide both sides by negative one"...?


lost here said:
y= -2/1x - 4
Why did "(-2x)/(-1)" become "(-2)/(1x)"? Why did "- (4)/(-1) = - (-4)" become "- 4"?

Of course, due to the ambiguity of your formatting, I could easily be misunderstanding what you're saying. If this is the case, please accept my apologies.

If you have further questions, please review the formatting explained in the "Karl's Notes" link in the "Forum Help" pull-down menu at the very top of the page, and then reply with clarification.

Thank you.

Eliz.
 
2x - y = -4

Start by changing the signs:
-2x + y = 4 : simple, right?

Add 2x to both sides:
y = 2x + 4

OK??
 
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