irritating word problem! please help!

I'm a homeschooled student and this problem is the last on a test. I don't know what's not clicking in my brain but I just can't figure out a formula. Can someone please help?

A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimeters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square centimeters greater than the first. What are the dimensions of the original rectangle?

I understand the first and second rectangles would look like this:

4w 4w+5
w [ ] w + 2 [ ]

but that's as far as I get! What would the formula look like?

Thanks in advance for any help!

A rectangle is 4 times as long as it is wide
length = L, width = W

L = 4W

A second rectangle is 5 centimeters longer and 2 centimeters wider than the first.
length = L', width = W'

L' = 4W+5
W' = W+2

The area of the second rectangle is 270 square centimeters greater than the first.

L'W' = 270 + LW

now ... do the substitutions that will get the last equation in terms of a single variable

(4W+5)(W+2) = 270 + (4W)(W)

solve for W ... the width of the original rectangle, then you can find all else.

Okay!

So the dimensions of the original rectangle are 20 and 80, which makes it's square footage 1,600, right?

Awesome, thank you very much, Skeeter!