Percentage calculation: which number 12% will be added....

S

santos

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Joined
Jun 20, 2006
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Hi.

I need help regarding below mentioned queries.

How could i calculate, In which NUMBER (number unknown) 12%(percentage known) will be added to get the resulting 2400 (known number).


Thanks
 
Re: Percentage calculation.

santos said:
How could i calculate, In which NUMBER (number unknown) 12%(percentage known) will be added to get the resulting 2400 (known number).
Click to expand...
X += .12X = 2400

1.12X == 2400

X = 2000
 
Uhh I think it would be more like this if I understand you q correctly:

\(\displaystyle \frac{.12x}{.12}=\frac{2400}{.12}\)
\(\displaystyle x=20,000\)

Check:

\(\displaystyle (20,000)(.12)=2400\)
 
well ... here's a third response for you. you'll have to be the judge on which one of us interpreted your problem correctly.

In which NUMBER (number unknown) 12%(percentage known) will be added to get the resulting 2400 (known number).
Click to expand...

let x = the unknown number

x + (12% of x) = 2400

x + .12x = 2400

x(1 + .12) = 2400

x(1.12) = 2400

x = 2400/1.12 = 2142.86 (rounded to two decimal places)
 
Denis said:
...may I have the envelope please... :roll:
Click to expand...
This is why it's so important (hint, hint!) to include the full and exact statement of the exercise, and the complete instructions. It is difficult to assist in finding the answer when we are befuddled as to what the actual question is. :shock:

Eliz.
 
thanks

Thank u very much everybody for helping instantly.

Thanks :lol:
 
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