Please help me with this one. I don't understand my teacher. . . .x/2 = 3
G Georgie New member Joined Jul 24, 2006 Messages 2 Jul 24, 2006 #1 Please help me with this one. I don't understand my teacher. . . .x/2 = 3
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Jul 24, 2006 #2 Think: Opposite, Undo, or Inverse. Goal: Make 'x' lonely - get it by itself. Ask: How are things attached to it? x/2 = 3 There's a '2' there. It is attached by division. Use multiplication to move it. 2*(x/2) = 2*(3) x*(2/2) = 6 x*(1) = 6 x = 6
Think: Opposite, Undo, or Inverse. Goal: Make 'x' lonely - get it by itself. Ask: How are things attached to it? x/2 = 3 There's a '2' there. It is attached by division. Use multiplication to move it. 2*(x/2) = 2*(3) x*(2/2) = 6 x*(1) = 6 x = 6
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Jul 24, 2006 #3 Georgie said: Please help me with this one. I don't understand my teacher. . . .x/2 = 3 Click to expand... Also remember that: if a/x = b/y, then ay = bx (crisscross multiplication) you have: x/2 = 3/1 : capish?
Georgie said: Please help me with this one. I don't understand my teacher. . . .x/2 = 3 Click to expand... Also remember that: if a/x = b/y, then ay = bx (crisscross multiplication) you have: x/2 = 3/1 : capish?