Weibull Distribution: determine first and second moments

Use integration to determine first and second moments of the Weibull distribution with parameters a, b, and c:

f(y) = (c/b)*((y - a)/b)^(c - 1) *exp{-((y - a)/b)^c) , a<y

Tan said:

f(y) = (c/b)*((y - a)/b)^(c - 1) *exp{-((y - a)/b)^c)

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Just to clarify, does the snippet quoted above mean the following?

. . . . .\(\displaystyle \L f(y)\,= \,\left(\frac{c}{b}\right)\, {\left(\frac{y\,-\,a}{b}\right)}^{c\,-\,1}\, e^{\left(\frac{-(y\,-\,a)}{b}\right)}^c\)

Thank you.

Eliz.

Yep tha would be the one.