Help with a word problem: A man invests $2200 in three accou

nikki26

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Interest: A man invests $2200 in three accounts that pay 6%,8%, and 9% annual interest, respectively. He has three times as much invested at 9% as he does at 6%. If his total interest for the year is $178, how much has he invested?

I dont know how to set this problem up. If some one would be so kind as to show me I would be grateful.
 
Break the problem up into linear equations.

Set up the interest:

\(\displaystyle \L\\.06x+.08y+.09z=178\)

3 times as much invested at 9% as 6%:

\(\displaystyle \L\\3x=z\)

Total amount invested:

\(\displaystyle \L\\x+y+z=2200\)


Now, do the appropriate subbings and you should be on your way.
 
Re: Help with a word problem

nikki26 said:
I dont know how to set this problem up. If some one would be so kind as to show me I would be grateful.
You might want to try following the step-by-step instructions provided to you in your earlier post on this exercise.

Thank you.

Eliz.
 
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