Functions- here is what i got for f(x)=2x^2-3x Simplify f(

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Bobbie

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suppose that f(x)=2x^2-3x.
simplify f(b)-f(a)/b-a
I got f(2b^2-3b)-f(2a^2-3a)/b-a = 2b^2-2a^2-3b+3a/b-a = 2(b-a)(b-a)+(a-b)/
b-a = 2(b-a)+3(a-b)

Help
[/u]
 
\(\displaystyle \L\\\frac{(2b^{2}-3b)-(2a^{2}-3a)}{b-a}=\frac{2b^{2}-3b-2a^{2}+3a}{b-a}=\frac{(b-a)(2a+2b-3)}{b-a}\)
 
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