suppose that f(x)=2x^2-3x. simplify f(b)-f(a)/b-a I got f(2b^2-3b)-f(2a^2-3a)/b-a = 2b^2-2a^2-3b+3a/b-a = 2(b-a)(b-a)+(a-b)/ b-a = 2(b-a)+3(a-b) Help [/u]