like terms: -5x-2[4x-2(3y-8)-(3x+2y)]

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kikis888

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Sep 17, 2006
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Sorry I am not getting this

-5x-2[4x-2(3y-8)-(3x+2y)]

I need to see the breakdown....please someone...thanks in advance.
 
The best procedure is usually to work from the inside out. So, for instance, your first step would be something along the lines of:

. . . . .-5x - 2[4x - 2(3y - 8) - (3x + 2y)]

. . . . .-5x - 2[4x - 2(3y - 8) - 1(3x + 2y)]

. . . . .-5x - 2[4x - 2(3y) - 2(-8)) - 1(3x) - 1(+2y)]

Simplify, and combine like terms. Then take the -2 through the brackets. And so forth.

If you get stuck, please reply showing how far you have gotten. Thank you.

Eliz.
 
ok so that would leave me with

-5x-2[4x-6y+16-3x-2y]

do i take the -2 and mutiply it to all numbers in the bracket?
 
kikis888 said:
ok so that would leave me with
-5x-2[4x-6y+16-3x-2y]
do i take the -2 and mutiply it to all numbers in the bracket?
Click to expand...

Next time, simplify BEFORE doing the multiplication:
-2[4x - 6y + 16 - 3x - 2y]
= -2[x - 8y + 16]
Now do the multiplications; easier on "your eyes" :wink:
 
thank you...simpifying it in the equation would make more sense. (a 53 yr old learning algebra for the 1st time...tytytytyty :idea:
 
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