Hi it's me again with yet another problem that I cant solve
I'm currently solving systems of equations which until now has been extremely simplistic. Now this book is changing coefficients on me and I'm completely lost :lol:
I solved the first one just fine
5a + 2b = -16
a + 3b = 15
so:
5(a + 3b) = 5(15)
or 5a + 15b = 75
then:
5a + 2b = -16
subtract
5a + 15b = 75
to get:
-13b = -91
b = 7
then solve for x
a + 3(7) = 15
a = -6
then I substituted x and y into the original problem and it worked...I thought I had the method down.
So I tried it for the second problem:
5d - 3e = 5
d - e = -1
so:
5(d - e) = 5(-1)
or:
5d - 5e = -5
now subtract
5d - 3e = 5
subtract
5d - 5e = -5
to get -2e = 10
e = -5
then:
d - -5 = -1
d = -6
substituting into the original problem does not yield the desirable results...somebody please help!
I'm currently solving systems of equations which until now has been extremely simplistic. Now this book is changing coefficients on me and I'm completely lost :lol:
I solved the first one just fine
5a + 2b = -16
a + 3b = 15
so:
5(a + 3b) = 5(15)
or 5a + 15b = 75
then:
5a + 2b = -16
subtract
5a + 15b = 75
to get:
-13b = -91
b = 7
then solve for x
a + 3(7) = 15
a = -6
then I substituted x and y into the original problem and it worked...I thought I had the method down.
So I tried it for the second problem:
5d - 3e = 5
d - e = -1
so:
5(d - e) = 5(-1)
or:
5d - 5e = -5
now subtract
5d - 3e = 5
subtract
5d - 5e = -5
to get -2e = 10
e = -5
then:
d - -5 = -1
d = -6
substituting into the original problem does not yield the desirable results...somebody please help!