A total of 52 dogs and cats were on the ranch. if three times the number of dogs exceeded the number of cats by four , how many of each were on the ranch?
3D + 4C = 52
subtract 4C from both sides
3D = 48
48/3
D=16
3(16) + 4C = 52
48 + 4C = 52
sybtract 48 from both sides
4C = 4
4/4
C = 1
check
3(16dogs) + 4(1cat) = 52 on the ranch
48dogs + 4cats = 52
52dogs&cats= 52 on the ranch
wrong
3D + 4C = 52
subtract 4C from both sides
3D = 48
48/3
D=16
3(16) + 4C = 52
48 + 4C = 52
sybtract 48 from both sides
4C = 4
4/4
C = 1
check
3(16dogs) + 4(1cat) = 52 on the ranch
48dogs + 4cats = 52
52dogs&cats= 52 on the ranch
wrong