Two kegs contain equal quantities of beer. From one keg

I just need help getting this problem started, please.

2 kegs contain equal quantities of beer. From one keg, 37 gallons are drawn. From the other, 7 gallons are drawn. The quantity remaining in one keg is now seven times that remaining in the other. How much did each keg contain at first?

i) Pick a variable for the number of gallons in a keg.

ii) In terms of this variable, write an expression for the amount remaining in the first keg after removing thirty-seven gallons.

iii) In terms of the variable in (i), write an expression for the amount remaining in the second keg after removing seven gallons.

iv) In terms of the expression in (iii), write an expression for "seven times" the amount remaining in this second keg.

v) In terms of the expressions in (ii) and (iv), write an equation for "the quantity remaining in the first keg" is (equals) "seven times the quantity remaining in the second keg".

vi) Solve the equation for the value of the variable chosen in (i).

If you get stuck, please reply showing how far you have gotten. Thank you.

Eliz.

Thanks for keg help

Liz
Thanks for helping with the keg problem