Poker Hands: how many are there with 3 aces and 2 kings?

J

jessieputono

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Sep 26, 2006
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Here's a question I cannot get...please help.

How many poker hands (five cards) are there with three aces and two kings?
 
\(\displaystyle \L {4 \choose 3} {4 \choose 2}\)
 
how come you put a 4 on the top?
is this answer the same thing: 5!/ (3!)(2!)?
 
anna said:
how come you put a 4 on the top?
is this answer the same thing: 5!/ (3!)(2!)?
Click to expand...

No, what pka posted is the same as C(4,3)*C(4,2)=24.

Just different notation.
 
This is fairly standard notation. The binomial coefficient is \(\displaystyle {N \choose k} = \frac{{N!}}{{k!\left( {N - k} \right)!}}\) is the expression for the number of ways to choose k items from N distinct kinds.
 
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