Word problem HELP?

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babyduckee

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Sep 28, 2006
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How many gallons of 65% antifreeze and how many gallons of 20% antifreeze should be mixed to obtain 50 gallons of a 56% mixture of antifreeze?
 
let x = amount of 65% antifreeze
50-x = amount of 20% antifreeze

x(.65) + (50-x)(.20) = (50)(.56)

solve for x and 50-x
 
so I broke it down after that to:

x(.65)+(50-x)(.20)=28

then:

x(.13)+(50-x)=28

Is this correct so far? If so what should i do next
 
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