solve for point on x-axis equidistant from (10,4) and (6,2)

If the point lies on the x-axis, then its y-coordinate must be 0.

\(\displaystyle \L\\\sqrt{(10-x)^{2}+(4-0)^{2}}=\sqrt{(6-x)^{2}+(2-0)^{2}}\)

Solve for x.
 
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