Please solve for the point on the x-axis that is equidistant from (10,4) and (6,2). Thanks
R runlemmingsrun New member Joined Sep 11, 2006 Messages 15 Oct 3, 2006 #1 Please solve for the point on the x-axis that is equidistant from (10,4) and (6,2). Thanks
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Oct 3, 2006 #2 If the point lies on the x-axis, then its y-coordinate must be 0. \(\displaystyle \L\\\sqrt{(10-x)^{2}+(4-0)^{2}}=\sqrt{(6-x)^{2}+(2-0)^{2}}\) Solve for x.
If the point lies on the x-axis, then its y-coordinate must be 0. \(\displaystyle \L\\\sqrt{(10-x)^{2}+(4-0)^{2}}=\sqrt{(6-x)^{2}+(2-0)^{2}}\) Solve for x.