homework help?

So i have a couple questions..well three.

1. Find the coordinates of the points on the graph of y=x³+2 at which
the slope of this tangent is 12.

y=x³+2
= 3x^2, slope is 12
Therefore, x much equal -2 and 2 in order for the slope to be 12. But im
unsure on how to find the y's.

2. Find the values of x so that the tangent to the function
y=3
----
³√x is parallel to the line x+16y+3=0.

y=3
---
³√x
= 3x^1/3
=-x^4/3

Im not sure how to find the slope of the line and i know if i had that i
could sub that into -x^4/3.

3. Find the slope of the tangent. y=2/x (-2, -1)
y=2/x (-2, -1)

=2x^-1
=2(-1/2)x^-2
=-x^-2
=-1
----
x^2

=-1
----
4

Im not sure if that is right or not, i doesnt look right to me.

Thanks for any help and i apologize if it is hard to understand, just tell
me and i will try my hardest to fix it.

"Slope of the tangent" isn't usually covered until calculus, and you've posted this question to "Beginning Algebra". What algebraic formula(s) and/or method(s) are you supposed to use to find slopes of tangents?

Please be specific. Thank you.

Eliz.