I am not sure if I am setting this problem up correctly.
The perimeter of a square is the same as the perimeter of a regular hexagon. If each side of the square is 7 feet longer than each side of the hexagon, what is the perimeter of each figure?
s+7(4) = 4s+28
4s + 28 = 6h
I am lost at this point.
The perimeter of a square is the same as the perimeter of a regular hexagon. If each side of the square is 7 feet longer than each side of the hexagon, what is the perimeter of each figure?
s+7(4) = 4s+28
4s + 28 = 6h
I am lost at this point.