Perimeter of a square is equal to a hexagon

I am not sure if I am setting this problem up correctly.

The perimeter of a square is the same as the perimeter of a regular hexagon. If each side of the square is 7 feet longer than each side of the hexagon, what is the perimeter of each figure?


s+7(4) = 4s+28

4s + 28 = 6h

I am lost at this point.

A hexagon has 6 sides.

The squares perimeter is 4s

The side of the hexagon is 7 less than the squares side.

Let h=length of hexagon side and s=length of square side.

\(\displaystyle 4s=6(s-7)\)

Solve for s, the length of the squares side. h will follow.