is my work right? solve 1/(3x/5)^2

gracierox77

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Sep 16, 2005
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In this problem: 1/(3x/5)^2

I solved:
1/1*(5/3x)^2

1/1*(25/9x)^2

25/9x^2

is this right?
 
IF you have it written as you intend, you MAY have it.

What is the difference between these two:

25/9x^2
25/(9x^2)

Or is there any difference.

Hint: Think "Order of Operations"
 
gracierox77 said:
In this problem: 1/(3x/5)^2 I solved: 1/1*(5/3x)^2
I'm going to guess you mean that you "simplified". If so, this first step is correct.

gracierox77 said:
1/1*(25/9x)^2
How did you go from "(5/3x)<sup>2</sup>" to "(25/9x)<sup>2</sup>"? Why did the 5/3 turn into a 25/9, while the x and the squaring stayed the same?

gracierox77 said:
If, in your previous step, you mean "(25/(9x<sup>2</sup>))" then, yes, this is okay. But otherwise, two "wrongs" have somehow "cancelled out" and magically produced a "right". This may not get credit now, and will almost certainly cause grave difficulties later (such as on tests).

Please check your work! :wink:

Eliz.
 
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